Problem: Find the equation of the plane tangent to the paraboloid z=2x2+y2 at (x,y,z)=(1,1,3).
Solution: Set f(x,y)=2x2+y2. Compute fx=4x, fy=2y. So fx(1,1)=4, fy(1,1)=2, and the linear approximation is given by:
L(x,y)=3+4(x−1)+2(y−1).
The tangent plane is found by setting z=L(x,y).